There are two spherical balls A and B of the same material with same surface, but the diameter of A is half that of B. If A and B are heated to the same temperature and then allowed to cool, then
A
Rate of cooling is same in both
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B
Rate of cooling of A is four times that of B
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C
Rate of cooling of A is twice that of B
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D
Rate of cooling of A is 14 times that of B
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Solution
The correct option is B Rate of cooling of A is four times that of B Rate of heat transfer by radiation = A x T4 Temperature is same for both spheres A = Surface area Surface area of sphere = π d2 Cooling rate of big sphere / Cooling rate of small sphere = d2 big / d2small
Hence cooling rate will takes place in the ratio of 4 : 1