Question

There are two types of grass, green grass, and pink grass. One cow eats green grass and the other eats pink grass. The region covered is as shown. Which cow ate more grass? (Units given here are in feet.)

• A. Cow that ate green grass.
• B. Cow that ate pink grass
• C. Both the cow ate equally.

Answer 1

The correct option is B Cow that ate pink grass


Let's mark the areas as shown.
Now, we know that a square has area $={\text{side}}^2$
Also, Area of a triangle
$=\frac{1}{2}\times \text{Base}\times \text{Height}$
Now, Let's calculate the area covered in green, i.e. $I+II$
Area $I=\frac{1}{2}\times 4\times 3=6$ sq. units.
Area $II=\frac{1}{2}\times 4\times (10-4)=12$ sq. units.
$\therefore \text{Area}I+\text{Area}II=12+6=18$ sq. units.
Similarly, let's calculate the area of $III\&IV$
Now, Area $III=\frac{1}{2}\times 3\times (10-4)=9$ sq. units
And, Area $IV=4\times 4=16$ sq. units
$\Rightarrow \text{Area}III+\text{Area}IV$
$=9+16=25$ sq. units.
$\therefore$ Area covered in pink is greater and hence, the cow eating grass in pink will consume more grass.