There are two values of time for which a projectile is at the same height (say $h$ ) from ground. If $T$ is the total time of flight for this projectile on level ground, then the sum, of these two times is equal to:

3 T / 2

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4 T / 3

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3 T / 4

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T

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Solution

The correct option is D $T$
$t_{O A} + t_{B C}$
To find $t_{O A} + t_{O B}$
$t_{O A} + t_{O B} = t_{B C} + (t_{O B}) = T$ .

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Similar questions

Q. There are two values of time for which a projectile is at the same height. The sum of these two times is equal to (

T

= time of flight of the projectile)

Q. Show that there are two values of time for which a projectile is at the same height. Also show that the sum of these two heights is equal to the time of flight

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Q. Assertion :If time of flight in a projectile motion is made two times, its maximum height will become four times. Reason: In projectile motion

H \propto T^{2},

where

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is maximum height and

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A projectile has the same range for two angles of projection. If times of flight in both cases are $t_{1}$ and $t_{2}$ then the range of the projectile is :

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There are two values of time for which a projectile is at the same height (say h) from ground. If T is the total time of flight for this projectile on level ground, then the sum, of these two times is equal to:

The correct option is D TtOA+tBCTo find tOA+tOBtOA+tOB=tBC+(tOB)=T.

There are two values of time for which a projectile is at the same height (say $h$ ) from ground. If $T$ is the total time of flight for this projectile on level ground, then the sum, of these two times is equal to:

The correct option is D $T$
$t_{O A} + t_{B C}$
To find $t_{O A} + t_{O B}$
$t_{O A} + t_{O B} = t_{B C} + (t_{O B}) = T$ .