Question

There are two vessels, A and B, each with a capacity of 100 litres. 80% of Vessel A is filled with milk and 90% of Vessel B is filled with water. The remaining portion of vessels A and B is empty. A milkman removed 25 litres of the milk from Vessel A and poured it into another Vessel C and then added 40 litres of water from Vessel B into it. He poured 40 litres of milk from Vessel A and 45 litres of water from Vessel B into Vessel D. Finally, he added the remaining water from Vessel B into Vessel A

It is known that the cost price of pure milk is Rs. $40$/litre. At what price the milkman should sell the mixture from Vessel D, such that he makes a profit of $70\%$ after selling this mixture? (Assume that water is free.)

• A. Rs. $36$
• B. None of these
• C. Rs. $34$
• D. Rs. $32$

Answer 1

The correct option is D Rs. $32$

Total amount of milk in the mixture of Vessel D = $40$ litres

Total amount of water in the mixture of Vessel D = $45$ litres

Total quantity of the mixture = $85$ litres

Total price of the mixture = $40\times 40=$ Rs. $1600$

To make a profit of $70\%$, the total selling price of the mixture should be $1600+70\%$ of
$1600=$ Rs. $2720$

Thus, the selling price of 1 litre of the mixture =$\frac{2720}{85}=$Rs.32

Hence, option A is the correct answer.