There are two wires of the same material. There radii and lengths are both in the ratio $1 : 2$ . If the extensions produce dare equal, what is the ratio of the loads?

1 : 2

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2 : 1

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1 : 4

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4 : 1

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Solution

The correct option is A $1 : 2$

Since both wire are of same material their young modules is same ; let extension be $△ l$
$f = \frac{S t r e r s}{S t r a i r} = \frac{F_{1} / A_{1}}{△ l / l_{1}} f = \frac{F_{2} / A_{2}}{△ l / l_{2}} \frac{F_{2}}{△_{2}} \frac{l_{2}}{△ l} = \frac{F_{1}}{△_{1}} \frac{l_{1}}{△ l} \frac{F_{1}}{F_{2}} = 2. \frac{1}{4} = 1 : 2$

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There are two wires of the same material. There radii and lengths are both in the ratio 1:2. If the extensions produce dare equal, what is the ratio of the loads?

The correct option is A 1:2Since both wire are of same material their young modules is same ; let extension be △lf=StrersStrair=F1/A1△l/l1f=F2/A2△l/l2F2△2l2△l=F1△1l1△lF1F2=2.14=1:2

There are two wires of the same material. There radii and lengths are both in the ratio $1 : 2$ . If the extensions produce dare equal, what is the ratio of the loads?