Question

There are two women participating in a chess tournament. Every participant played two games with the other participants. The number of games that the men played between themselves proved to exceed by 66 the number of games that the men played with the women. How many games were played?

• A. 78
• B. 210
• C. 156
• D. 128

Answer 1

The correct option is C

156

Let the number of men = n

Number of games between men and women = 4n

Given that $2{(}^n{C}_2-2n)=66$

Solving for n, we get n= 11

Thus total number of games played = ${}^{13}{C}_2=78\times 2=156$