Question

There exists a value of $\theta$ between $0$ and $2\pi$ which satisfies the equation $si{n}^4\theta -2si{n}^2\theta -1=0$. If true enter 1 else 0.

Answer 1

${\sin }^4\theta -2{\sin }^2\theta +1=2\Rightarrow {({\sin }^2\theta -1)}^2=2\Rightarrow {\sin }^2\theta =\pm \sqrt{2}+1$
Which is not possible , hence given statement is false