There is a box containing 15 ping pong balls of 3 different colors red, green and blue. There are 7 red balls and 3 green balls. What is the probability of getting a blue ball in the first attempt?

$\frac{1}{2}$

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$\frac{1}{3}$

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$\frac{1}{4}$

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$\frac{1}{5}$

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Solution

The correct option is B
$\frac{1}{3}$

Given,

Total number of balls = 15

Red balls = 7

Green balls = 3

Blue balls = 15 - (7+3) = 15 - 10 = 5

P(blue ball) = $\frac{N u m b e r o f b l u e b a l l s}{T o t a l n u m b e r o f b a l l s}$ = $\frac{5}{15}$ = $\frac{1}{3}$

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There is a box containing 15 ping pong balls of 3 different colors red, green and blue. There are 7 red balls and 3 green balls. What is the probability of getting a blue ball in the first attempt?

The correct option is B 13 Given, Total number of balls = 15 Red balls = 7 Green balls = 3 Blue balls = 15 - (7+3) = 15 - 10 = 5 P(blue ball) = Number of blue ballsTotal number of balls = 515 = 13

The correct option is B
$\frac{1}{3}$

Given,

Total number of balls = 15

Red balls = 7

Green balls = 3

Blue balls = 15 - (7+3) = 15 - 10 = 5

P(blue ball) = $\frac{N u m b e r o f b l u e b a l l s}{T o t a l n u m b e r o f b a l l s}$ = $\frac{5}{15}$ = $\frac{1}{3}$