Question

There is a five digit number. The fourth digit is 4 greater than second digit, while third digit is 3 less than second digit. The first digit is thrice the last digit. These are three pairs whose sum
is 11. Find the number.

• A. $35291$
• B. $65292$
• C. $63072$
• D. $95293$

Answer 1

Answer: (B)

$65292$

Let the five digit number is ABCDE.
According to question
A$=$ 3E
$D=B+4$
$C=B-3$
From equation (i), E can be 1, 2 or 3
From equations (ii) and (iii). B can be 3, 4 or 5.
So, A can be 3, 6 or 9
B can be 3, 4 or 5
C can be 0, 1 or 2
D can be 7, 8 or 9
and E can be 1, 2 or 3
Now. the sum of three pairs is 11. This condition is satisfied by the number 65292.