Question

There is a hole in the bottom of tank having water. If total pressure at bottom is 3 atm (1 atm = ${10}^5$N/$m^2$) then the velocity of water flowing from hole is

• A.
• B.
• C.
• D. None of these

Answer 1

The correct option is A

Pressure at the bottom of tank $P=h\rho g=3\times {10}^5\frac{N}{m^2}$

Pressure due to liquid column

$P_1=3\times {10}^5-1\times {10}^5=2\times {10}^5$

and velocity of water $v=\sqrt{2gh}$

$\therefore v=\sqrt{\frac{2P_1}{\rho }}=\sqrt{\frac{2\times 2\times {10}^5}{{10}^3}}=\sqrt{400}m/s$