Question

There is a hole in the bottom of tank having water. If total pressure at bottom is 3 atm (1 atm = ${10}^{5}N/m^2$) then the velocity of water flowing from hole is:

• A. $\sqrt{400}m/s$
• B. $\sqrt{600}m/s$
• C. $\sqrt{60}m/s$
• D. None of these

Answer 1

The correct option is A $\sqrt{400}m/s$

Pressure at the bottom of tank $P=h\rho g=3x{10}^5\frac{N}{m^2}$
Pressure due to liquid column
$P_1=3x{10}^5-1x{10}^5=2x{10}^5$
and velocity of water $v=\sqrt{2gh}$
$\therefore v=\sqrt{\frac{2P_1}{\rho }}=\sqrt{\frac{2x2x{10}^5}{{10}^3}}=\sqrt{400}m/s$