Question

There is a hole of area A at the bottom of cylindrical vessel. Water is filled up to a height h and water flows out in t second. If water is filled to a height 4h, it will flow out in time equal to

• A. t
• B. 4t
• C. 2t
• D. t/4

Answer 1

The correct option is C

2t

Time required to emptied the tank $t=\frac{A}{A_0}\sqrt{\frac{2H}{g}}$

$\therefore \frac{t_2}{t_1}=\sqrt{\frac{H_2}{H_1}}=\sqrt{\frac{4h}{h}}=2\therefore t_2=2t$