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Standard XII

Physics

Apparent Depth

There is a ho...

Question

There is a hole to the wall at the bottom of a vessel filled with water to a height $10 c m$ . Water flows out completely in $5 s e c$ . If the height of the water column above the hole is increased to $160 c m$ , the total time taken for water flow is

2.5 s e c

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5 s e c

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10 s e c

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20 s e c

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Solution

The correct option is C $20 s e c$
we have formula,

$\frac{t_{2}}{t_{1}} = \sqrt{\frac{H_{2}}{H_{1}}}$

$\frac{t_{2}}{5} = \sqrt{\frac{160}{10}}$

$= t_{2} = 5 \times 4 = 20 s e c$

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There is a hole to the wall at the bottom of a vessel filled with water to a height 10 cm. Water flows out completely in 5 sec. If the height of the water column above the hole is increased to 160 cm, the total time taken for water flow is

The correct option is C 20 secwe have formula,t2t1=√H2H1t25=√16010=t2=5×4=20sec

There is a hole to the wall at the bottom of a vessel filled with water to a height $10 c m$ . Water flows out completely in $5 s e c$ . If the height of the water column above the hole is increased to $160 c m$ , the total time taken for water flow is

The correct option is C $20 s e c$
we have formula,

$\frac{t_{2}}{t_{1}} = \sqrt{\frac{H_{2}}{H_{1}}}$

$\frac{t_{2}}{5} = \sqrt{\frac{160}{10}}$

$= t_{2} = 5 \times 4 = 20 s e c$