There is a path of uniform width 7 m round and outside a circular garden of diameter 210 m. Find the area of the path.

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Solution

Diameter =210 m

Radius of inner circule $r_{2} = 105 m$

Width =7m

Radius of outer circle $r_{1} = 105 + 7 = 112 m$

$∴$ Area of path $= π r_{1}^{2} - π r_{2}^{2}$

$= π [r_{1}^{2} - r_{2}^{2}]$

$= \frac{22}{7} (r_{)} 1 + r_{2}) (r_{1} + r_{2})$

$= \frac{22}{7} (112 + 105)$

(112-105)

$= \frac{22}{7} \times 217 \times 7$

$= 4774 m^{2}$

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There is a path of uniform width 7 m round and outside a circular garden of diameter 210 m. Find the area of the path.

Diameter =210 m Radius of inner circule r2=105m Width =7m Radius of outer circle r1=105+7=112m ∴ Area of path =πr21−πr22 =π[r21−r22] =227(r)1+r2)(r1+r2) =227(112+105) (112-105) =227×217×7 =4774m2