The correct option is B 8
Given, a provision will last 10 days for 12 students.
We know that,
Number of students(x)∝1Number of days(y)
x1x2 = y2y1
Given,
x1 = 12 students
x2 = 15 students
y1 = 10 days
and, y2 = number of days forwhich the provision will last for 15 students
⇒1215 = y210
⇒y2 = 12×1015 = 8 days