There is a regular octagonal park. The surface area of the park is ___ (in $m^{2}$ )

119

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120

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200

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100

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Solution

The correct option is A
119

The octagon can be divided into two trapeziums and a rectangle by joining vertices as shown below:

$A r e a o f O c t a g o n = (2 \times A r e a o f t r a p e z i u m) + A r e a o f r e c t a n g l e$

$= 2 \times [\frac{1}{2} \times (5 + 11) \times 4] + 5 \times 11$

$= 119 m^{2}$

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