There is a remainder of $3$ when a number is divided by $6$ . What will be the remainder if
the square of the same number is divided by $6$ ?

1

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0

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3

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2

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Solution

The correct option is C $3$
$L e t t h e n u m b e r b e x ∴ x = 6 q + 3 (w h e r e q i s t h e q u o t i e n t a n d q \neq 0) F o r x t o b e l e a s t q s h o u l d b e 1. ∴ x = 6 \times 1 + 3 = 9 ∴ x^{2} = 81 T h e d i v i s o r i s 6. ∴ 81 = 6 \times 13 + 3 ∴ R e m a i n d e r = 3 A n s w e r - O p t i o n C$

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Similar questions

A number, when divided by 6, leaves a remainder 3. When the square of that number is divided by 6, the remainder is 3.

A number when divided by 6 leaves a remainder 3. When the square of the number is divided by 6, the remainder is 3.

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