There is a sample of $10$ volume of hydrogen peroxde solution. Calculate its strength.

3.00 %

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4.045 %

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2.509 %

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3.035 %

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Solution

The correct option is D $3.035 %$
$(H_{2} O_{2} ⟶ H_{2} O + 1 / 2 O_{2}) \times 2$
$2 H_{2} O_{2} 68 g ⟶ 2 H_{2} O + O_{2} (224 L at NTP)$
$∵ 224 L$ $O_{2}$ at $N T P$ obtained by $68 g$ of $H_{2} O_{2}$ .
$∴ 10 L$ $O_{2}$ at $N T P$ obtained by $(68 / 22.4) \times 10 = 30.35 g / L$
$∴ 1000 m l$ $O_{2}$ at $N T P$ obtained= $30.35 g$
$∴ 100 m l$ $O_{2}$ at $N T P$ obtained= $\frac{30.35}{1000} \times 100 = 3.035$ %

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