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EMF and EMF Devices

There is a se...

Question

There is a series $L - C - R$ circuit.An alternating source of emf having voltage $V = V_{0} sin ω t$ is applied between M and N
Here $V_{M} - V_{N} = V_{0} sin ω t$ and $\frac{1}{ω C} - ω L = R$

A

θ = \frac{π}{2}

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B

θ = 0

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C

θ = \frac{π}{4}

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D

θ = π

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Solution

The correct option is D $θ = \frac{π}{4}$
$tan θ = \frac{\frac{1}{w l} - w l}{R}$
given $\frac{l}{w l} - w L = R$
$tan θ = \frac{R}{R} = L$
$θ = \frac{π}{4}$

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