Question

There is a series $L-C-R$ circuit.An alternating source of emf having voltage $V=V_0\sin \omega t$ is applied between M and N
Here $V_M-V_N=V_0\sin \omega t$ and$\frac{1}{\omega C}-\omega L=R$

• A. $\theta =\frac{\pi }{2}$
• B. $\theta =0$
• C. $\theta =\frac{\pi }{4}$
• D. $\theta =\pi$

Answer 1

Answer: (C)

$\theta =\frac{\pi }{4}$

$\tan \theta =\frac{\frac{1}{wl}-wl}{R}$
given $\frac{l}{wl}-wL=R$
$\tan \theta =\frac{R}{R}=L$
$\theta =\frac{\pi }{4}$