There is a set of 4 tuning forks, one with lowest frequency vibrating at 552 Hz. By using any two forks at time, the beat frequencies heard are 1,2,3,5,7,8. The possible frequencies of other three forks are.
A
553,554 and 560 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
553,555 and 560 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
553,556 and 558 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
551,554 and 560 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A553,554 and 560 Hz
f1= lowest
=552Hz Let (f1<f2<f3<f4)
Different type of beat frequencies that can be heard =4C2=6
i.e =(1,2,3,5,7,8)
max beat freq =fmax−fmm=8
⇒f4−f1=8
⇒f4−552=8
⇒f4=560Hz
Now, f4−f2=7
560−f2=7
⇒f2=553Hz
We have-
f2−f1=1,
f4−f2=7,
f4−f1=7,
⇒f4−f3=5
⇒560−f3=5
⇒f3=555
I am getting answer 553Hz, 555Hz, 560Hz
But given answer is-
553,554 and 560Hz
But this answer is wrong.
If we consider two frequencies 554Hz and 560Hz then beat freq =6Hz
but 6Hz is not given in the list of beat frequencies in the question. So, the given answer is wrong.