Question

There is a small hole at the bottom of tank filled with water. If total pressure at the bottom is 3 atm (1 atm $={10}^{5}N{m}^{-2})$, then velocity of water flowing from hole is

• A. $\sqrt{400}m{s}^{-1}$
• B. $\sqrt{600}m{s}^{-1}$
• C. $\sqrt{60}m{s}^{-1}$
• D. None of these

Answer 1

The correct option is A $\sqrt{400}m{s}^{-1}$

$\Delta p=\frac{1}{2}\rho v^2$
$\therefore$ $v=\sqrt{\frac{2\Delta p}{\rho }}$
$=\sqrt{\frac{2(3atm-1atm)}{\rho }}$
$=\sqrt{\frac{2\times 2\times {10}^5}{{10}^3}}=\sqrt{400}$ m/s