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Question

There is a small hole in a spherical shell of mass M and radius R. A particle of mass m is dropped from point A as shown. Match the two columns for the situation shown in figure.

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Solution

Since UG=GMm/r outside the sphere therefore, from A to B continously decreases.
A->2
potential energy inside a hollow sphere remains constant therefore,
B->4
Since potential energy is constant therefore, KE will rermain constant and so as velocity of particle.
C->4
Since, gravitstional force outside the sphere is FG=GMm/r3 therefore, from A to B acceleration increases then remains constant i.e zero inside the sphere.
D->3

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