There is a stream which flows for 15 km. I have a boat with speed 14 $\frac{k m}{h r}$ and a stream with speed x $\frac{k m}{h r}$ . In how much time can I travel upstream and downstream respectively?Write an expression for that.

(14/15-x), (14/15+x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(15/14+x), (15/14-x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(15/14-x), (15/14+x)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(14/15+x), (14/15-x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
(15/14-x), (15/14+x)

Time = $\frac{d i s t a n c e}{s p e e d}$

Distance = 15 km

Upstream speed = 14-x(Stream flows against boat)

Downstream speed = 14 + x(Stream flows with boat)

Upstream time = $\frac{D i s t a n c e}{u p s t r e a m s p e e d}$

= ( $\frac{15}{14}$ -x)

Downstream time = $\frac{D i s t a n c e}{d o w n s t r e a m s p e e d}$

= ( $\frac{15}{14}$ +x)

Suggest Corrections

Similar questions

There is a stream which flows for 15 km. I have a boat with speed 14 km/hr and a stream with speed x km/hr. Write an expression for the time it takes to travel upstream and downstream respectively.

Q. A boat goes

15 k m

upstream and

22 k m

down stream in

15

hours. In

14

hours it can go

45

upstream and

55 k m

down stream. The speed of the boat in still water in

k m / h r

Q. Mode of the data

15, 14, 19, 20, 14, 15, 16, 14, 15, 18, 14, 19, 15, 17, 15

Q. The mode of the following numbers is-

15, 14, 19, 20, 14, 15, 16, 14, 15, 18, 14, 19, 15, 17, 15

Q. If

(1 + x)^{15} = C_{0} + C_{1} x + C_{2} x^{2} + . . . . . . + C_{15} x^{15},

then

C_{2} + 2 C_{3} + 3 C_{4} + . . . . . . + 14 C_{15} =

Join BYJU'S Learning Program

There is a stream which flows for 15 km. I have a boat with speed 14 kmhr and a stream with speed x kmhr. In how much time can I travel upstream and downstream respectively?Write an expression for that.

The correct option is C (15/14-x), (15/14+x) Time = distancespeed Distance = 15 km Upstream speed = 14-x(Stream flows against boat) Downstream speed = 14 + x(Stream flows with boat) Upstream time = Distanceupstreamspeed = (1514-x) Downstream time = Distancedownstreamspeed = (1514+x)

There is a stream which flows for 15 km. I have a boat with speed 14 $\frac{k m}{h r}$ and a stream with speed x $\frac{k m}{h r}$ . In how much time can I travel upstream and downstream respectively?Write an expression for that.