There is a thin metal plate of length and breadth 2M mm and 2K mm respectively. Its thickness is 1 mm. If ‘N’ number of plates are placed one on top of the other, what is the object formed and what is its volume in mm3?
A
Cuboid, MKN
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Cuboid, 4MKN
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Sphere, 4MKN
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cylinder, 2 MKN
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B Cuboid, 4MKN Thickness of 1 plate = 1 mm. Total thickness of N plates put together = N mm The object formed has now 3 dimensions- Length, breadth and thickness. The area of one plate =Length×Breadth =2M×2K =4MKmm2 The object formed when thin plates are stacked together is nothing but a cuboid. This can be visualised as shown below.
Volume=PlateArea×Totalthickness =4MK×N =4MKNmm3
[Note that, if M=K=12, then length, breadth and thickness are equal and hence the resulting solid will be a cube. But cube is a special case of cuboid. So, the given answer is correct in this case too.]