Question

There is a two digit number ab. Its reversed number is obtained by interchanging the digits as ba. Sum of ab and ba is 77 and one's place of the number is 3. What is the digit at ten's place of the number?

• A. 7
• B. 2
• C. 4
• D. 3

Answer 1

The correct option is C

4

(10a + b) + (10b + a) = 77
b = 3

Thus, 10a + 3 + 30 + a = 77

⇒ 11a + 33 = 77 ⇒ a = 4