There is an air bubble of radius $R$ inside a drop of water of radius $3 R$ . Find the ratio of gauge pressure at point $A$ to the gauge pressure at point $B$ to that at point A.

\frac{1}{2}

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\frac{1}{4}

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\frac{1}{3}

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Solution

The correct option is C $\frac{1}{3}$

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Q. Suppose there is an air bubble of radius

\frac{R}{2}

inside the air cavity of radius R inside a water drop of radius 3R as shown in figure. The ratio of gauge pressure at point C to gauge pressure at point B is :

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in air is equal to the excess pressure inside air bubble of radius

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