There is an auditorium with 35 rows of seats. There are 20 seats in the first row, 22 seats in the second row, 24 seats in the third row and so on. Find the number of seats in the twenty-third row.
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Solution
Seats are to be arranged as 20 in the first row, 22 in the second row, 24 in the third row, and so on. ∴ Here a=20,d=22−20=2 We have to find a23. We know that an=a(n−1)d a23=20+(23−1)×2 =20+22×2 =20+44 =64