There is an electric field E in x − direction. If the work done on moving a charge of 0.2C through a distance of 2m along a line making an angle 60∘ with x − axis is 4J, then what is the value of E ?
A
5NC
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B
20NC
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C
√3NC
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D
4NC
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Solution
The correct option is B20NC
Given that Work done W=4J charge q=0.2C displacement s=2m angle of motion with the electric field θ=60∘ We know that work done is given by W=F.s⇒W=Fscosθ⇒W=qEscosθ Putting values we get ⇒W=0.2×E×2×cos60∘ ⇒E=20N/C