Question

There is an electric field in the $+x$-direction. If the work done on moving a charge of $0.2\text{C}$ through a distance of $2\text{m}$ along a line making an angle of ${60}^{\circ }$ with $+x$ axis is $4\text{J}$. The value of $E$ is ?

• A. $4{\text{NC}}^{-1}$
• B. $\sqrt{3}{\text{NC}}^{-1}$
• C. $5{\text{NC}}^{-1}$
• D. $20{\text{NC}}^{-1}$

Answer 1

The correct option is D $20{\text{NC}}^{-1}$



$W=Fd$

$W=qE\cos {60}^{\circ }d$

$W=0.2\times E\times \left(\frac{1}{2}\right)\times 2$

$4=0.2\times E\times \left(\frac{1}{2}\right)\times 2$

$E=\frac{4}{0.2}=\frac{40}{2}=20{\text{NC}}^{-1}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (d) is the correct answer.