Question

There is no change in the hybridization of $B$ and $N$ atoms as a result of the following reaction:

${BF}_3+{NH}_3\to F_{3}B.{NH}_3$

• A. True
• B. False

Answer 1

The correct option is B False

There are 3 bond pair and 0 lone pairs in $B{F}_3$, so the hybridisation of $B{F}_3$ is $s{p}^2$ and in $N{H}_3$ there are 3 bond pair and 1 lone pair. So, hybridisation of $N{H}_3$ is $s{p}^3$

After the reaction, hybridisation of B changes $s{p}^3$ but hybridisation of N remains the same because N shares its lone pair with electron deficient B.

So the correct option is False.