There is no perfect cube that ends with $8$ (True or False)

True

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False

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Solution

The correct option is B False
Let us take a number $8$
Find out the cube root of $8$
$\sqrt[3]{8} = \sqrt[3]{2 \times 2 \times 2} = 2$
Take another example,
Let us take a number $1728$
Find out the cube root of $1728$
$\sqrt[3]{1728} = \sqrt[3]{12 \times 12 \times 12} = 12$
Therefore, we can clearly see that there is a perfect cube that number ends with $8$
Hence, the given statement is $f a l s e$

Suggest Corrections

Similar questions

State true or false.

(i) Cube of any odd number is even.

(ii) A perfect cube does not end with two zeroes.

(iii) If square of a number ends with 5, then its cube ends with 25.

(iv) There is no perfect cube which ends with 8.

(v) The cube of a two digit number may be a three digit number.

(vi) The cube of a two digit number may have seven or more digits.

(vii) The cube of a single digit number may be a single digit number.

Question 2(ii)

State True or False.
A perfect cube does not end with two zeroes.

Write true (T)I or false (f) for the followiong statements:
(i) 392 is a perfect cube.
(ii) 8640 is not a perfect cube.
(iii) No cube can end with exactly two zeros.
(iv) There is no perfect cube which ends in 4.
(v) For an integer $a, a^{3}$ is always greater than $a^{2}$
(vi) if a and b are integers such that $a^{2} > b^{2}, t h e n a^{3} > b^{3}$
(vii) If a adivides b, then $a^{3}$ divides $b^{3}$
(viii) If $a^{2}$ ends in 9 then $a^{3}$ ends in 7.
(ix) If $a^{2}$ ends in 5, then $a^{3}$ ends in 25.
(x) If $a^{2}$ ends in an even number of zeros. than $a^{3}$ ends in an odd number of zeros.

Question 2(iv)

State True or False.
There is no perfect cube which ends with 8.

Q. State true or false:

There is no perfect cube which ends with

8

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There is no perfect cube that ends with 8 (True or False)

There is no perfect cube that ends with $8$ (True or False)