Question

There unbiased coins are tossed. What is the probability of getting atmost $2$ heads?

• A. $\frac{3}{4}$
• B. $\frac{1}{4}$
  
• C. $\frac{3}{8}$
• D. $\frac{7}{8}$

Answer 1

Answer: (D)

$\frac{7}{8}$

Three coins were tossed.

Outcomes with almost two heads are: $E=\{TTT,TTH,THT,HTT,THH,HHT,HTH\}$

Required probability $=1-$ Probability of getting three heads.

$=1-\frac{1}{8}=\frac{7}{8}$