There was $10$ liters of pure milk in a vessel. $2$ liters of milk was withdrawn from it and $2$ liters of water was mixed. Again two liters of liquid was withdrawn from the mixture and $2$ liters of water was mixed. If this process is repeted thrice; then the ratio of milk and water in the final mixture.

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Solution

The Process is repeated thrice

First Time :- Milk = 10-2=8 L
Water = 2 L

Second Time :- Milk = 8-2 =6 L
Water = 2+2=4 L

Third Time :- Milk = 6-2=4 L
Water = 4+2 =6 L

Hence, Ratio in Final Mixture $= 4 : 6 = 2 : 3$

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There was 10liters of pure milk in a vessel. 2liters of milk was withdrawn from it and 2liters of water was mixed. Again two liters of liquid was withdrawn from the mixture and 2liters of water was mixed. If this process is repeted thrice; then the ratio of milk and water in the final mixture.

The Process is repeated thriceFirst Time :- Milk = 10-2=8 L Water = 2 L Second Time :- Milk = 8-2 =6 L Water = 2+2=4 L Third Time :- Milk = 6-2=4 L Water = 4+2 =6 LHence, Ratio in Final Mixture =4:6=2:3

The Process is repeated thrice

First Time :- Milk = 10-2=8 L
Water = 2 L

Second Time :- Milk = 8-2 =6 L
Water = 2+2=4 L

Third Time :- Milk = 6-2=4 L
Water = 4+2 =6 L

Hence, Ratio in Final Mixture $= 4 : 6 = 2 : 3$