There will be a term independent of x in the expansion of (xa+x−b)n only if
A
an is a multiple of (a+b).
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B
ab is a multiple of (a+b).
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C
True for all n
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D
None of these
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Solution
The correct option is Dan is a multiple of (a+b). In the above question Tr+1=nCrxan−arx−br =nCrxan−r(a+b) For a term independent of x an−r(a+b)=0 r=ana+b Since r has to be a whole number, an has to be a multiple of (a+b).