Question

There will be zeros at the end of the number ${11000}^2$.

• A. $6$
• B. $8$
• C. $4$
• D. $3$

Answer 1

The correct option is A $6$

The number ${11000}^2$ can be written as
$(11\times 1000{)}^2={11}^2\times {10}^{3\times 2}$

It is evident that ${10}^2$ ends with two zeros, ${10}^3$ ends with three zeros and so on.
Therefore, ${10}^{3\times 2}$ will end with $3\times 2$ i.e. 6 zeros.

Hence, ${11}^2\times {10}^{3\times 2}$ will end with $6$ zeros.