Question

Thermal capacity of $20\text{g}$ of copper is (Given:Specific heat $=0.1\text{cal/g-K}$)

• A. $2\text{cal}/{}^{\circ }\text{C}$
• B. $2\text{cal/ K}$
• C. $8.4\text{J/K}$
• D. All of the above

Answer 1

The correct option is D All of the above

We know,
Thermal capacity $=mC=20\times 0.1$
$=2{\text{cal/}}^{\circ }\text{C}$
$=2\text{cal/K}$
$=2\times 4.2\text{J/K}[\because 1\text{cal}=4.2\text{J}]$
$=8.4\text{J/K}$