Thermal capacity of $40 g$ of aluminum (specific heat $= 0.2 c a l /^{\circ} C$ ) is?

40 c a l /^{\circ} C

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160 c a l /^{\circ} C

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200 c a l /^{\circ} C

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8 c a l /^{\circ} C

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Solution

The correct option is D $8 c a l /^{\circ} C$
Given: Mass of aluminum=40g
Specific heat = $0.2 c a l^{0} C^{- 1}$
Solution: Thermal capacity of a substance is that property which allow it to absorb heat when it is heated and release heat when it is cooled.
It is given by,
Thermal Capacity= $m \times s$
where, m denotes the mass and s denotes the specific heat.
Substituting the values we get,
$= 40 \times 0.2$
$= 8 c a l^{0} C^{- 1}$
Hence, the correct option is (D).

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Thermal capacity of 40g of aluminum (specific heat =0.2cal/∘C ) is?

Thermal capacity of $40 g$ of aluminum (specific heat $= 0.2 c a l /^{\circ} C$ ) is?