Thermal conductivity of the conductor shown in the figure is 0.92cal/cm s∘C. Find the thermal resistance between points P and Q (in s∘C/cal).
A
0.036
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B
0.018
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C
0.072
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D
1
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Solution
The correct option is A0.036 Given,
Thermal conductivity (K)=0.92cal/cm s∘C
Then, from the definition,
Thermal resistance (R)=lKA
From P to Q, area of cross-section perpendicular to PQ is uniform i.e (A=lb) and length along PQ is h=2cm. ∴R=20.92×60=0.036s∘C/cal