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Question

Thermal conductivity of the conductor shown in the figure is 0.92 cal/cm sC. Find the thermal resistance between points P and Q (in sC/cal).


A
0.036
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B
0.018
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C
0.072
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D
1
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Solution

The correct option is A 0.036
Given,
Thermal conductivity (K)=0.92 cal/cm sC
Then, from the definition,
Thermal resistance (R)=lKA
From P to Q, area of cross-section perpendicular to PQ is uniform i.e (A=lb) and length along PQ is h=2 cm.
R=20.92×60=0.036 sC/cal

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