Question

Thermal decomposition of $AgN{O}_3$ produces two paramagnetic gases. The total number of electrons present in the antibonding molecular orbitals of the gas that has the higher number of unpaired electrons is.

• A. 6.0
• B. 6
• C. 6.00

Answer 1

Answer: (A), (B), (C)

\( \begin{aligned} 2 AgNO _{3} \stackrel{\Delta}{\rightarrow} & Ag _{2} O ( s )+2 NO _{2}( g ) \\ & \|_{ Ag }^{ A }( s )+1 / 2 O _{2}( g )\end{aligned} \)
Both $N{O}_2$ and $O_2$ are paramagnetic as $N{O}_2$ has only unpaired electron while $O_2$ has two unpaired electrons. Electronic configuration of $O_2\left(16\right)$ is
$\left(\sigma 1s{)}^2\right({\sigma }^{\ast }1s{)}^2\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2\left(\sigma 2p_z{)}^2\right(\pi 2p_x^2=\pi 2p_y^2\left)\right({\pi }^{\ast }2p_x^1={\pi }^{\ast }2p_y^1)$
Total number of electrons in antibonding orbitals is $=6$