Thermodynamically $H X e O_{4}^{-}$ should oxidise water, but reaction does not take place. It is due to the fact__________.

that there is a high activation energy barrier between oxidation state +6 to 0

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that standard emf is positive

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that

Δ G^{\circ} = + v e

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that

Δ G^{\circ} = - v e

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Solution

The correct option is A that there is a high activation energy barrier between oxidation state +6 to 0
As $Δ G^{0} = - n F E^{0}$ , so thermodynamically it should oxidise but activation energy barrier between oxidation state +6 to 0 is very high so reaction doesn't takes place.

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△ G .

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