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Standard VII

Mathematics

Integers

Think of a po...

Question

Think of a positive number, say $x$ . From the square of this number, subtract three times of itself. If the result is $10$ , then $x$ is equal to

2

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Solution

The correct option is C $5$
The number is $x$ .
Then, $x^{2} - 3 x = 10$
$x^{2} - 5 x + 2 x - 10 = 0$
$(x - 5) (x + 2) = 0$
$∴ x = 5$

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Think of a positive number, say x. From the square of this number, subtract three times of itself. If the result is 10, then x is equal to

The correct option is C 5The number is x.Then, x2−3x=10x2−5x+2x−10=0(x−5)(x+2)=0∴x=5

Think of a positive number, say $x$ . From the square of this number, subtract three times of itself. If the result is $10$ , then $x$ is equal to

The correct option is C $5$
The number is $x$ .
Then, $x^{2} - 3 x = 10$
$x^{2} - 5 x + 2 x - 10 = 0$
$(x - 5) (x + 2) = 0$
$∴ x = 5$