Question

Thionyl chloride $\left(SOC{l}_2\right)$ is preferred for preparing alkanoyl chloride because

• A. side products are gaseous
• B. purification of alkanoyl chloride becomes easier
• C. $SOC{l}_2$ act as autocatalyst
• D. Both (a) and (b)

Answer 1

The correct option is D Both (a) and (b)

Carboxylic acid reacts with $PC{l}_3$ or $PC{l}_5$ or $SOC{l}_2$ to produce alkanoyl chloride.
Among them thionyl chloride $\left(SOC{l}_2\right)$ is preffered for preparing alkanoyl chloride because the other two products are gaseous and escape the reaction mixture. It makes the purification of alkanoyl chloride easier.
Hence, option (d) is correct.