Question

Thiosulphate ion $\left(S_2{O}_3^{2-}\right)$ on acidification changes to $S{O}_2$ along with precipitation of sulphur,
${}^{35}{S}^{32}S{O}_3^{2-}+2H^{+}⟶H_{2}O+S{O}_2+S$
which is the correct statement?

• A. $S^{35}$ is in sulphur
• B. $S^{35}$ is in $S{O}_2$
• C. $S^{35}$ is in both
• D. $S^{35}$ is in none

Answer 1

Answer: (A)

$S^{35}$ is in sulphur

${}^{32}{SO}_3^{2-}+2H^{+}⟶H_{2}O+{SO}_2+2e^{-}{}^{}{}^{32}{SO}^{2-}+2e^{-}{⟶}^{35}S$
So ${}^{35}S$ is in product sulpher (option A)