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Thirty women were examined in a hospital by a doctor and the number of heart beats per minute were recorded and summarized as follows. Fine the mean heart beats per minute for these women, choosing a suitable method.

Number of heart beats per minute68­7171747477778080838386Number of Women2438742

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Solution

Given data is,

Number of heart beats per minute68­7171747477778080838386Number of Women2438742

To find the class mark of each interval (xi), the following relation is used.

xi=Upper class limit+Lower class limit2

Class size, h of this data =3

Taking 75.5 as assumed mean (a), di and ui are calculated as follows.

Number of heart beats per minuteNumber of Womenxidi=xiaui=di3fiui6568266.59366871469.56267174372.53167477875.50067780778.53168083481.56268386284.5936Totalfi=30fiui=4

From the table,

fi=30

fiui=4

size of the class interval h=3.

Mean =a+(fiuifi)h

=75.5+(430)×3

=75.5+410

=75.5+0.4

=75.9

Therefore, mean hear beats per minute for these women are 75.9 beats per minute.


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