This conversion can be achieved by.

M e_{2} C O / H^{+}, H_{3} O^{\oplus}, K M n O_{4} / H O^{-}

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M e_{2} C O / H^{+}, K M n O_{4}, H_{3} O^{+}

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K M n O_{4} / N a O_{4}, M e_{2} C O / H^{+}, H_{3} O^{+}

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K M n O_{4} / N a I O_{4}, H_{3} O^{+}, M e_{2} C O / H^{+}

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Solution

The correct option is B $M e_{2} C O / H^{+}, K M n O_{4}, H_{3} O^{+}$

(Refer to Image)
Acetal is not affected by $K M n O_{4}$

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