This line $l x + m y = n$ is normal to the hyperbola passess through the focus,
then the line can be

Transverse axis

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Latus rectum

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Conjugate Axis

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Directrix

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Solution

The correct option is A Transverse axis
Given: Line $l x + m y = n$

Given line is a normal to the hyperbola and we have given that line passes through focus, then this line can only be transverse axis.

As transverse axis is the only normal of the hypebola that passes through the focus.

Suggest Corrections

Similar questions

b^{2} x^{2} - a^{2} y^{2} = a^{2} b^{2}

l x + m y + n = 0

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

l x + m y = n

b^{2} x^{2} - a^{2} y^{2} = a^{2} b^{2}

l x + m y + n = 0

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1.

l x + m y - n = 0

\frac{a^{2}}{l^{2}} - \frac{b^{2}}{m^{2}} = \frac{(a^{2} + b^{2})^{2}}{k}

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