wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question


Three 2 Ω resistors, A, B and C, are connected as shown in the Figure. Each of them dissipates energy and can withstand a maximum power of 18W without melting. Find the maximum current that can flow through the three resistors.

79886_67b414bd5d4340d49af44416828f3c91.png

A
3 A.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6 A.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
18 A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Data insufficient
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 6 A.
The power in a circuit is given as P=IV. The power in terms of current and resistance can be derived from the above equation as follows.
We know that from Ohm's law, V=IR. Substituting this in the above equation, we have P=I(IR), that is P=I2R.
The resistance across B and C is 1 ohm as they are parallelly connected. The total resistance in the circuit is 2+1=3ohms.
Given that the power is 18 W and the total resistance is 3 ohms, the maximum current across the circuit is calculated as follows.
P=I2R That is, I=PR=183.

flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PN Junction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon