Three 2 Ω resistors, A, B and C, are connected as shown in the Figure. Each of them dissipates energy and can withstand a maximum power of 18W without melting. Find the maximum current that can flow through the three resistors.
A
3 A.
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B
√6 A.
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C
√18 A
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D
Data insufficient
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Solution
The correct option is B√6 A. The power in a circuit is given as P=IV. The power in terms of current and resistance can be derived from the above equation as follows. We know that from Ohm's law, V=IR. Substituting this in the above equation, we have P=I(IR), that is P=I2R. The resistance across B and C is 1 ohm as they are parallelly connected. The total resistance in the circuit is 2+1=3ohms. Given that the power is 18 W and the total resistance is 3 ohms, the maximum current across the circuit is calculated as follows. P=I2R That is, I=√PR=√183.