Question

Three angle of a quadrilateral measure ${100}^o,{82}^o$ and ${68}^o$ find the Measure of the fourth angles-

Answer 1

$Sumofanglesofaquadrilateral={360}^{\circ }\therefore {100}^{\circ }+{82}^{\circ }+{68}^{\circ }+x={360}^{\circ }orx={360}^{\circ }-{250}^{\circ }={110}^{\circ }$