Question

Three angles of a quadrilateral are respectively equal to ${110}^o$, ${50}^o$ and ${40}^o$. Find the fourth angle.

• A. ${160}^o$
• B. ${140}^o$
• C. ${120}^o$
• D. ${100}^o$

Answer 1

The correct option is A ${160}^o$

Sum of all angles of a quadrilateral is ${360}^0$
Then fourth angle will be = ${360}^0-({110}^0+{50}^0+{40}^0)$
= ${160}^0$

Hence, the fourth angle is ${160}^0$